A uniform bridge 6.0 m long, weight 1200 N, rests on supports at its ends. A car of weight 8000 N stands 1.5 m from the left support. Find the support forces.
Take moments about the left support, which removes RL:
RR×6.0=1200×3.0+8000×1.5=15600, so RR=2600 N.
Vertical equilibrium: RL=9200−2600=6600 N.
Check with moments about the right support: 6600×6.0=39600 and 1200×3.0+8000×4.5= ✓.